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 pi code | Reply The code: if (precision==1) return "3.1"; if (precision==2) return "3.14"; if (precision==3) return "3.142"; should be replaced with:string pi = "3.1415926535897932384626433832795028841971"; return pi.substring(0, precision + 2);
 Re: pi code (response to post by Cosmin.ro) | Reply In that problem you should also round the last digit, so your solution will not work.
 Re: pi code (response to post by OlexiyO) | Reply Ok, it can be easily changed to solve that, but a 25 if statement solution shouldn't be suggested in any educational content article.
 Re: pi code (response to post by Cosmin.ro) | Reply Works for me!http://www.topcoder.com/stat?c=problem_solution&rm=202836&rd=7221&pm=4470&cr=301395
 Re: pi code (response to post by HardCoder) | Reply :) yeah but you have a different purpose recently, most people want to increase their rating, not generate forum threads about their solutions :P. These type of solutions are useful in SRMs when the algorithm for getting a result takes more than 2 seconds, the rest of the time they just decrease your score.
 Re: pi code (response to post by Cosmin.ro) | Reply It also required you to have exactly those many digits. My code was something in between: here :-)
 Re: pi code (response to post by aboyner) | Reply So my code is between yours and HardCoders, since for some reason it has the HardCodered value for 12 :)I don't know how could I miss that so have you.
 Re: pi code (response to post by slex) | Reply Since aboyner's also has the answer for 12 hardcoded, I think yours is between his and his.
 Re: pi code (response to post by Kawigi) | Reply I wish I were there when easy ones were really easy :(import java.math.BigDecimal;   public class PiCalculator { public String calculate(int precision) { BigDecimal easy = new BigDecimal("3.141592653589793238462643383279"); easy = easy.divide(BigDecimal.ONE, precision, BigDecimal.ROUND_HALF_UP); return easy.toString(); } }
 Re: pi code (response to post by darko_aleksic) | Reply My favorite (too easy) one was also mentioned by the feature - FormatAmt could be solved in Java by "return java.text.NumberFormat.getCurrencyInstance().format(dollars + cents/100.0);" Of course, you had to know that's what it did and you had to assume that TopCoder runs your code under a US locale. Too bad I wasn't in that SRM, because I learned that over and over again when I was a TA :-)
 Re: pi code (response to post by Kawigi) | Reply Tad shorter in VB: return format(dollars+(cents/100),"\$###,###,###,##0.00")
 Forums News, Programs & Events Discussions A Number or a String... (Article) pi code